0=12x^2-26x+20

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Solution for 0=12x^2-26x+20 equation: 



0=12x^2-26x+20

We move all terms to the left:

0-(12x^2-26x+20)=0

We add all the numbers together, and all the variables

-(12x^2-26x+20)=0

We get rid of parentheses

-12x^2+26x-20=0

a = -12; b = 26; c = -20;
Δ = b2-4ac
Δ = 262-4·(-12)·(-20)
Δ = -284
Delta is less than zero, so there is no solution for the equation

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